sciandu
Mathematics

Mathematics

Complex numbers

The square root of a negative number does not exist? That is exactly where a new set of numbers begins.

Every time a calculation did not work out, the set of numbers was extended. 353 - 5 had no answer until negative numbers existed. 1:31 : 3 had none until fractions existed. 2\sqrt{2} had none until irrational numbers existed. Now 1\sqrt{-1} is on the table, and the trick is the same as always: give the missing answer a name and see whether you can calculate with it sensibly.

The number i

You define i2=1i^2 = -1. So ii is the number whose square is 1-1, and it is called the imaginary unit. The name is historical and really rather unfair, because ii is just as usable as any other number. With it, every root of a negative number can be written down: 9=3i\sqrt{-9} = 3i, because (3i)2=9i2=9(3i)^2 = 9 \cdot i^2 = -9.

i2=1i^2 = -1
The single definition everything else follows from.

Two parts, one number

A complex number consists of an ordinary part and a multiple of ii, for example z=3+4iz = 3 + 4i. The 3 is called the real part, the 4 the imaginary part. Together they form a single number, just as 3.5 is a single number and not two. The set of all these numbers is called C\mathbb{C}, and the real numbers sit inside it completely: they are simply the complex numbers with imaginary part 0.

You calculate as if ii were a variable, and at the very end you replace every i2i^2 by 1-1. So adding means: real parts together, imaginary parts together. (3+4i)+(12i)=4+2i(3 + 4i) + (1 - 2i) = 4 + 2i. Multiplying works by expanding brackets as usual: (3+4i)(12i)=36i+4i8i2(3 + 4i)(1 - 2i) = 3 - 6i + 4i - 8i^2. The last two steps: 6i+4i=2i-6i + 4i = -2i, and 8i2=+8-8i^2 = +8. What remains is 112i11 - 2i.

The number plane

Real numbers live on a number line. For complex numbers a line is not enough, because they carry two pieces of information. So you take a plane: the real part goes to the right, the imaginary part upwards. This picture is called the complex plane, and every complex number is a point in it. The distance from the origin is called the modulus and is worked out with Pythagoras: 3+4i=32+42=5|3 + 4i| = \sqrt{3^2 + 4^2} = 5.

Coordinate grid
x3
y2
-6-6-4-4-2-2224466
P (3 | 2)
Read the grid as the complex plane: xx is the real part, yy the imaginary part. Set the point to (3|4), which is the number 3+4i3 + 4i with modulus 5. Then set it to (3|−4), the conjugate 34i3 - 4i: same distance from the origin, mirrored across the horizontal axis. Points on the xx axis such as (5|0) are ordinary real numbers.

What this is good for

With complex numbers every quadratic equation has a solution. x2+1=0x^2 + 1 = 0 has none over the reals, but two over the complex numbers: x=ix = i and x=ix = -i. When the is negative, you simply take the root of its size and write an ii next to it. This is not a useless trick: alternating current, signal processing and quantum physics all calculate with complex numbers, because are far easier to describe that way.

Exercises

0 of 6 solved

Time to try it yourself. You can't break anything, every attempt counts.

How is the imaginary unit ii defined?

What is the real part of z=72iz = 7 - 2i?

Work out (2+3i)+(45i)(2 + 3i) + (4 - 5i).

25=\sqrt{-25} =

Work out i4i^{4}.

Match each number to where it sits in the complex plane.

44
4i4i
4+4i4 + 4i