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Mathematics

Mathematics

Cylinder, cone & sphere

Three round solids, three formulas, one shared core: everything builds on the area of a circle.

For a , volume is easy: length times width times height. As soon as something is round, formulas often get guessed. That is not necessary, because cylinder, cone and sphere belong together. All three formulas contain the circle area πr2\pi r^2, and the differences fit into a single sentence.

The cylinder: circle times height

A cylinder is a can: a circle at the bottom, the same circle on top, straight walls in between. Exactly as for a cuboid it is base area times height, except the base is now a circle. So V=πr2hV = \pi r^2 \cdot h. A can with r=4r = 4 cm and h=10h = 10 cm has a volume of π1610503\pi \cdot 16 \cdot 10 \approx 503 cm³, so about half a litre.

Circle gauge
Radius r4
r = 4
U = 2 · π · r = 25.1A = π · r² = 50.3
The core of all three formulas sits here. Set r=3r = 3: the circle area is about 28.3 and the circumference about 18.8. From those two numbers you get everything. A cylinder of height 10 has volume 28.310=28328.3 \cdot 10 = 283, a cone with the same base only a third of that, so about 94. And the lateral surface of the cylinder is the circumference times the height, so 18.810=18818.8 \cdot 10 = 188.

For the surface of a can you need three parts: two circles and the wall. Unrolled, the wall is a rectangle. Its height is hh, and its width is the circumference 2πr2 \pi r, because that is exactly how far it reaches around. So O=2πr2+2πrhO = 2 \pi r^2 + 2 \pi r h.

The cone: a third of it

A cone has the same base as a cylinder but tapers to a point. It fits exactly three times into the cylinder of the same height. That is why the formula has a third in it: V=13πr2hV = \frac{1}{3} \pi r^2 h. You can genuinely test this by filling a cone-shaped cup with water three times and pouring it into a cylindrical one of the same height and radius.

A cone has two different lengths, and mixing them up is the classic mistake. The height hh runs vertically from the middle of the circle to the tip. The slant height ss runs from the edge of the circle to the tip and is always longer. The two are linked by Pythagoras: s2=r2+h2s^2 = r^2 + h^2. For the volume you need hh, for the surface you need ss.

The sphere: only the radius counts

A sphere has no height and no base, it only has a radius. Accordingly both formulas contain nothing but rr and π\pi: V=43πr3V = \frac{4}{3} \pi r^3 and O=4πr2O = 4 \pi r^2. The surface formula is easier to remember than it looks: it is exactly four times the circle area. So a football with r=11r = 11 cm has a surface of 4π12115214 \pi \cdot 121 \approx 1521 cm².

VZyl=πr2hVKegel=13πr2hVKugel=43πr3V_{\text{Zyl}} = \pi r^2 h \qquad V_{\text{Kegel}} = \tfrac{1}{3}\pi r^2 h \qquad V_{\text{Kugel}} = \tfrac{4}{3}\pi r^3
The cylinder is the benchmark, the cone is a third of it, and the sphere needs no height.

Exercises

0 of 6 solved

Time to try it yourself. You can't break anything, every attempt counts.

How do you work out the volume of a cylinder?

A can has a radius of 5 cm and a height of 12 cm. What is its volume? Round to whole cm³.

A cone has a radius of 3 cm and a height of 8 cm. What is its volume? Round to one decimal place, in cm³.

The volume of a cone is of the volume of a cylinder with the same base and height.

A cone has a radius of 6 cm and a height of 8 cm. How long is its slant height ss in cm?

Match each solid to its volume formula.

Cylinder
Cone
Sphere